Kumar, Anil; Ghose, M. K.
2011-01-01
This paper proposes an extended substitution-diffusion based image cipher using chaotic standard map [1] and linear feedback shift register to overcome the weakness of previous technique by adding nonlinearity. The first stage consists of row and column rotation and permutation which is controlled by the pseudo-random sequences which is generated by standard chaotic map and linear feedback shift register, second stage further diffusion and confusion is obtained in the horizontal and vertical pixels by mixing the properties of the horizontally and vertically adjacent pixels, respectively, with the help of chaotic standard map. The number of rounds in both stage are controlled by combination of pseudo-random sequence and original image. The performance is evaluated from various types of analysis such as entropy analysis, difference analysis, statistical analysis, key sensitivity analysis, key space analysis and speed analysis. The experimental results illustrate that performance of this is highly secured and fast.
I'd like to use java to make a cipher of sorts, but im not sure how to go about it.
Caesar Cipher Decoder
Basically, I'd want the machine to accept a string of text, say 'Abcd'
Program Kriptografi Caesar Cipher Dengan Javascript
and then a key, say '4532'
The program should move the characters forward in the alphabet if the number matching the place of the letter is even, and backward if it's odd.
If there is no number, the key should loop around until it's out of characters in the string to change.
the program would then print the key. Ideally, if im pseudocoding this correctly, deciphering the string would be a reverse process only applicable with the key.
I'm guessing i'd use a combination of an array and if/else statements.
I'm not sure where to start.
Example & edit String: 'hello' Key: '12' Soulja boy kiss me thru the phone download mp3 song.
a b c d e f g h i j k l m n o p q r s t u v w x y z
Because the corresponding key value is 1, h will travel backwards that many spaces.
h = g Miley jab hum tum all songs mp3 free download.
because e has a 2, it'll move forward that many spaces.
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e = g
the first l then becomes k, while the second becomes n. The Key is repeated because the string is out of numbers to compare. o turns into n because it's matched with 1.
hello would become ggknn with the key 42.
3 Answers
Here are possible steps you can take to do this. This is not an exact and working solution, but it will hopefully get you started.
- Start by reading input from the console (via
Scanner
or aBufferedReader
for example). - Split your input on spaces perhaps, so that you have a
String[]
of words. - Loop through the
String[]
of words, and loop again for which word. You can have a counter that is incremented in each iteration of an inner loop and gets reset at the end of an inner loop. You can use that counter variable to get a position into the key (key[counter%lengthOfKey]
) in each iteration of the inner loop. If the(counter%lengthOfKey)%2 0
, you have the even number case for the key, else the odd numbered case. Do whatever encryption at that point (simple substitution cipher for example).
There are many methods of Encryption, but if you want to learn about Encryption you should start with the study of XOR encryption. XOR Encryption uses a key and XORs the binary code of every character with the key. If the key is longer than the encrypted code it creates a One-Time Pad that is impossible to decrypt.
![Program Kriptografi Caesar Cipher Dengan Java Program Kriptografi Caesar Cipher Dengan Java](https://xenoposeidon.files.wordpress.com/2011/05/kripto1-stemahograph.png)
XOR - Exclusive OR - Unlike OR both values can not be true at the same time.
Simple Explanation:
- Pretend you want to encrypt the string 'hello world' with the key 'c'.
- For every character in the string XOR it with the key c.
Pretend the binary value of h is 1100011 and the binary value of c is 0010110 (these are made up and will not work) then you XOR every corresponding binary value.
1110101 is the XORed binary value.
- You then cast the binary value back into character and you do this for every step of the encrypted string.
Problems:
Insecure for short keys. but very powerful for long keys and creates a one time pad.
Example code: